{"id":611,"date":"2025-02-26T13:48:04","date_gmt":"2025-02-26T12:48:04","guid":{"rendered":"https:\/\/dev-site.se\/sutars.com\/?page_id=611"},"modified":"2026-05-15T09:54:44","modified_gmt":"2026-05-15T07:54:44","slug":"why-is-the-charging-performance-so-poor","status":"publish","type":"page","link":"https:\/\/sutars.com\/en\/wired-inspired\/charging-generators\/why-is-the-charging-performance-so-poor\/","title":{"rendered":"Why is the charging performance so poor?"},"content":{"rendered":"\t\t
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Why is the charging performance so poor?<\/h1>\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t
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Home<\/a> \/<\/span> Page<\/span><\/div>\t\t<\/div>\n\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t
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How voltage drop and cable dimensioning influence your battery charging performance<\/h2>\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t
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Lead-acid batteries are normally charged at a maximum of 14.4 V to avoid overcharging. Half-discharged lead-acid batteries have an open-circuit voltage of 12.3 V. A larger difference between the open-circuit voltage and the charging voltage allows the battery to be charged faster.<\/p>

If you want to charge at 14.4 V and your batteries are half discharged, you get a difference of 2.1 V. If you have a battery isolator diode installed, there will be a voltage drop of 0.7 V, reducing the difference to 1.4 V.<\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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If you also have undersized cables and poor connections, you can easily get an additional 0.4 V of voltage drop. That puts you down to a 1.0 V difference, which is less than half of 2.1 V. In other words, you only get half of the charging you could have had.<\/p>

With better connections and cables, and without a diode-type battery isolator, many users can double their charging.<\/p>

That\u2019s why Skyllermarks has long been asking: \u201cWho wouldn\u2019t want double charging?\u201d<\/b><\/span><\/p>\t\t\t\t\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t<\/div>\n\t\t\t\t

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